How many tablespoons are in 93 grams of potassium ferricyanide?

To determine the number of tablespoons in 93 grams of potassium ferricyanide, you need to know the density of potassium ferricyanide. The density of potassium ferricyanide is approximately 1.85 grams per cubic centimeter (g/cm³).

Therefore, the volume of 93 grams of potassium ferricyanide can be calculated as follows:

Volume = Mass / Density

Volume = 93 g / 1.85 g/cm³

Volume ≈ 50.3 cm³

Since 1 tablespoon is approximately equivalent to 14.7868 cm³, we can calculate the number of tablespoons as follows:

Number of tablespoons = Volume / Volume of 1 tablespoon

Number of tablespoons ≈ 50.3 cm³ / 14.7868 cm³/tablespoon

Number of tablespoons ≈ 3.4

Therefore, there are approximately 3.4 tablespoons in 93 grams of potassium ferricyanide.