A drove of sheep and chickens have a total 99 heads feet There are twice as many sheepHow each there?

Let's represent the number of sheep as "s" and the number of chickens as "c".

From the given information, we know that:

Total number of heads = s + c = 99

Total number of feet = 4s + 2c = 99 * 2

We are also given that there are twice as many sheep as chickens, so:

s = 2c

Substituting this into the second equation, we get:

4s + 2c = 99 * 2

4(2c) + 2c = 99 * 2

10c = 198

c = 19.8

Since we can't have a fraction of a chicken, we can round this up to 20 chickens.

Substituting this back into the first equation, we get:

s + c = 99

s + 20 = 99

s = 79

Therefore, there are 79 sheep and 20 chickens.