How much NaCl could be produced from 70.91 g of Cl2?

To calculate the amount of NaCl that can be produced from 70.91 g of Cl2, we can use the stoichiometry of the reaction between chlorine gas (Cl2) and sodium metal (Na) to form sodium chloride (NaCl). The balanced chemical equation for this reaction is:

Cl2(g) + 2Na(s) → 2NaCl(s)

From the equation, we can see that 1 mole of Cl2 reacts with 2 moles of Na to produce 2 moles of NaCl. The molar mass of Cl2 is 70.90 g/mol, while the molar mass of NaCl is 58.44 g/mol.

Using stoichiometry, we can calculate the number of moles of Cl2 in 70.91 g of Cl2:

Moles of Cl2 = Mass of Cl2 / Molar mass of Cl2

= 70.91 g / 70.90 g/mol

= 1.000 mol

Since 1 mole of Cl2 produces 2 moles of NaCl, the number of moles of NaCl that can be produced from 1.000 mol of Cl2 is:

Moles of NaCl = Moles of Cl2 × 2

= 1.000 mol × 2

= 2.000 mol

Finally, we can calculate the mass of NaCl produced by converting moles of NaCl to grams using its molar mass:

Mass of NaCl = Moles of NaCl × Molar mass of NaCl

= 2.000 mol × 58.44 g/mol

= 116.88 g

Therefore, 70.91 g of Cl2 can produce 116.88 g of NaCl.