What is the pH of 1 part vinegar plus 9 parts water?

To determine the pH of the mixture, we need to consider the dissociation of acetic acid (CH3COOH) present in vinegar. When vinegar is diluted with water, the concentration of acetic acid decreases, leading to a decrease in the hydrogen ion (H+) concentration. This results in a higher pH.

Vinegar typically has a pH between 2 and 3. When one part of vinegar is mixed with nine parts of water, the resulting dilution factor is 1:10. Assuming the original pH of vinegar is 3, the pH of the mixture can be estimated as follows:

pH = pH of vinegar - log(dilution factor)

pH = 3 - log(1/10)

pH = 3 - 1

pH = 2

Therefore, the pH of 1 part vinegar plus 9 parts water is approximately 2. This indicates a slightly acidic solution. It's important to note that the exact pH value may vary slightly depending on the specific concentration of acetic acid in the original vinegar.