What is the molarity of vinegar?

The molarity of vinegar depends on the concentration of acetic acid in the vinegar. Vinegar typically contains between 4% and 12% acetic acid by volume. The molarity of a solution is defined as the number of moles of solute per liter of solution. To calculate the molarity of vinegar, we need to know the density of the vinegar and the percentage of acetic acid by volume.

The density of vinegar is approximately 1.00 g/mL. This means that 1 liter of vinegar has a mass of 1000 g. If we assume that the vinegar contains 5% acetic acid by volume, then 1 liter of vinegar will contain 50 g of acetic acid.

The molecular weight of acetic acid is 60.05 g/mol. This means that 50 g of acetic acid is equivalent to 50 g / 60.05 g/mol = 0.833 moles of acetic acid.

Therefore, the molarity of a vinegar that contains 5% acetic acid by volume is 0.833 moles / 1 liter = 0.833 M.

Vinegar with a higher percentage of acetic acid will have a higher molarity, while vinegar with a lower percentage of acetic acid will have a lower molarity.