How many ways can a dinner patron select 3 appetizers and 2 vegetables if there are 6 5 on the menu?

Here's how to solve this problem:

1. Combinations for Appetizers

* We need to choose 3 appetizers out of 6.

* The formula for combinations is nCr = n! / (r! * (n-r)!), where n is the total number of items and r is the number you choose.

* So, the number of ways to choose 3 appetizers is 6C3 = 6! / (3! * 3!) = 20

2. Combinations for Vegetables

* We need to choose 2 vegetables out of 5.

* Using the combinations formula: 5C2 = 5! / (2! * 3!) = 10

3. Total Combinations

* To get the total number of ways to select appetizers and vegetables, we multiply the number of combinations for each: 20 * 10 = 200

Answer: There are 200 ways a dinner patron can select 3 appetizers and 2 vegetables.