What is the current in 30-ohm heating coil of a coffee maker that operates on 120 volt circuit?

Using Ohm's law:

$$I=\frac{V}{R}$$

Where:

- \(I\) is the current in amperes (A)

- \(V\) is the voltage in volts (V)

- \(R\) is the resistance in ohms (\(\Omega\))

Substituting the given values, we get:

$$I=\frac{120 V}{30 \Omega}$$

$$I=4 A$$

Therefore, the current in the 30-ohm heating coil of the coffee maker is 4 amperes.