How much more alcohol does a 6 percent can of beer have compared to 3.2 beer?

To determine the difference in the alcohol content between a 6 percent can of beer and a 3.2 percent beer, we need to calculate the amount of alcohol in each. We will assume that both cans have the same volume for simplicity.

1. 6 percent beer:

Alcohol content = (6% / 100) * volume of the can

Assuming the can is 355 milliliters (a typical size),

Alcohol content = (6 / 100) * 355 mL

Alcohol content ≈ 21.3 mL of pure alcohol

2. 3.2 percent beer:

Alcohol content = (3.2% / 100) * volume of the can

For the same can size (355 mL),

Alcohol content = (3.2 / 100) * 355 mL

Alcohol content ≈ 11.36 mL of pure alcohol

3. Difference in alcohol content:

To find the difference, we subtract the alcohol content of 3.2 percent beer from that of 6 percent beer:

Difference = Alcohol content in 6% beer - Alcohol content in 3.2% beer

Difference = 21.3 mL - 11.36 mL

Difference ≈ 9.94 mL of pure alcohol

Therefore, the 6 percent can of beer has approximately 9.94 mL more alcohol compared to the 3.2 beer in a can of the same volume.