Twenty pounds of dried fruit mix contained prunes worth 2.90 a pound and apricots 3.15 how many each did the contain if was 2.95 pound?

Let \(x\) be the number of pounds of prunes and \(y\) be the number of pounds of apricots. We have the following system of equations:

$$x + y = 20$$

$$2.90x + 3.15y = 2.95(20)$$

Solving the first equation for \(x\), we get:

$$x = 20 - y$$

Substituting this into the second equation, we get:

$$2.90(20 - y) + 3.15y = 59$$

Simplifying, we get:

$$58 - 2.90y + 3.15y = 59$$

Combining like terms, we get:

$$0.25y = 1$$

Dividing both sides by 0.25, we get:

$$y = 4$$

Substituting this back into the first equation, we get:

$$x + 4 = 20$$

Subtracting 4 from both sides, we get:

$$x = 16$$

So the dried fruit mix contained 16 pounds of prunes and 4 pounds of apricots.